By Arthur L. Kimball
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Extra resources for A College Text-Book Of Physics
FlO. 29. 61. -When a body is hung by a cord or balanced on a point the center of gravity must be in the vertical line passing through the point of support. For two equilibrating forces must act in the same straight line. If, therefore, a body is hung first from one point and then from another the intersection of the two lines thus determined marks the position of the center of gravity, as shown in the figure, where it is seen to be a point outside the actual substance of the chair. The center of gravity of a uniform bar is at its center; in a uniform thin plate, square, rectangular, or in the form of a parallelogram, it is at the intersection of the diagonals.
If, therefore, a body is hung first from one point and then from another the intersection of the two lines thus determined marks the position of the center of gravity, as shown in the figure, where it is seen to be a point outside the actual substance of the chair. The center of gravity of a uniform bar is at its center; in a uniform thin plate, square, rectangular, or in the form of a parallelogram, it is at the intersection of the diagonals. In case of any homogeneous symmetrical body it lies in the plane of symmetry.
4.. At what point on a pole must a weight of 52 lba. be hung so that a boy at one end may carry ~ as much as the man at the other end, Ilnd how much does each carry? Neglcd the weight of the pole. 6. , where must a 5O-1b. weight be hung 90 that the man may carry twice as much weight as the boy? 6. Find the center of gravity of a uniform bar weighing 6 lba. and having a 2-lb. weight on one end and a 7-lb. weight on the other. 7. Forces 2 and 4 actillg upward are applied 'to a horizontal bar at 2 ft.